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Please help with the following algebra problems. Provide step by step calculations as well as explanations. If possible, provide an additional example. The equation of a line is given below. Find the slope of a line that is:a. Parallel to the line with the given equation.
b. Perpendicular to the line with the given equation.Problem: The equation of a line is given below. Find the slope of a line that is:
a. Parallel to the line with the given equation.
b. Perpendicular to the line with the given equation.Solution:
Your question is missing the specific equation that you want answers for, but this is a basic question that can be answered easily with the following information.Question 1) For any line, the slope intercept form of the equation of the line is as shown below: y=m*x+bWhere the variables are as follows: m = slope
x = the independent variable of the domain
y = the dependent variable of the range
b = the y-intercept, which is the value of y for where the line crosses the y-axisSo the slopes of parallel lines, l1 & l2 are equal. We can say that m1=m2.Question 2) The slopes of perpendicular lines can be found where:m1*m2=-1, so m1=-1/m2 or m2=-1/m1. We word this so that the slope of one perpendicular line is equal to the negative reciprocal of the slope of the other perpendicular line. Example: Since you omitted the example, Ill create one.Consider the following two equations:
y=3*x+5
y=3*x-2These lines will be parallel to each other. The first line crosses the y-axis at y=5. The second at y= -2.Taking the first line of the following equation: y=3*x+5A line perpendicular to this line would have a slope of -1/3.So if b for the perpendicular line was 10, the formula for this perpendicular line would be the following equation:y= (-1/3)x + 10Good luck on your assignment!

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